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7 March, 09:18

A stack of 45 dimes is divided into three piles in the ratio 1/6 : 1/3 : 1/4.

1. How many dimes are in the pile with the least number of dimes?

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Answers (2)
  1. 7 March, 09:25
    0
    Answer: 10 dimes

    the pile with the least number of dimes have 10 dimes

    Step-by-step explanation:

    Given;

    Total number of dimes of the stack = 45

    Ratio of division into piles = 1/6 : 1/3 : 1/4

    Multiplying the ratio through by 12.

    12 (1/6 : 1/3 : 1/4) = 2 : 4 : 3

    The least number of dimes in a pile (Nl) is that of the least ratio; which is 2

    Ni = 2 / (2+4+3) * 45

    Ni = 2/9 * 45

    Ni = 10 dimes

    Therefore, the pile with the least number of dimes have 10 dimes
  2. 7 March, 09:46
    0
    10 dimes

    Step-by-step explanation:

    First we get rid of the fractions. Multiply everything by 12. So the new ratio is 2:4:3. Then add 2+3+4 which is 9. So 45/9=5, and 5*2 (which is the smallest number in the ratio) is 10. So the answer is 10 dimes.
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