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Bo Solomon
Mathematics
30 January, 16:15
Evaluate h (x) = - x2+1 for x=3
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Ronin Page
30 January, 16:42
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H (3), jsut subsitute 3 for x
h (3) = - (3) ^2+1
h (3) = - (9) + 1
h (3) = - 9+1
h (3) = - 8
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Gillian Cherry
30 January, 16:45
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H (3) = - 3*2 + 1 = - 5
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