Suppose you can factor x^2 + bx + c as (x + q) (x + q). If c>0, what could be possible values of p and q?

A. p=5, q=-8

B. p=-2, q=6

C. p=-4, q=-7

D. p=-13, q=1

The correct answer for the question that is being presented above is this one: "C. p=-4, q=-7." Suppose you can factor x^2 + bx + c as (x + q) (x + q). Given that c>0, the possible values of p and q are - 4 and - 7. When you multiply p and q, the value becomes positive, which makes c > 0.