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6 June, 08:03

Find the cube roots of 8. Write the answer in a + bi form.

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Answers (2)
  1. 6 June, 08:07
    0
    z = 2, - 1 + sqrt (3) i, - 1 + sqrt (3) i

    Step-by-step explanation:

    z³ = 8[cos (0) + isin (0) ]

    z = 8^⅓ = 2

    z = {8[cos (2pi) + isin (2pi) ]}^⅓

    z = 2[cos (2pi/3) + isin (2pi/3) ]

    z = - 1 + sqrt (3) i

    z = {8[cos (4pi) + isin (4pi) ]}^⅓

    z = 2[cos (4pi/3) + isin (4pi/3) ]

    z = - 1 - sqrt (3) i
  2. 6 June, 08:21
    0
    The answer is D
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