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21 February, 19:16

A new youth activity center is being built in Erie. The perimeter of the rectangular playing field is 490 yards. The length of the field is 5 yards less than quadruple the width. What are the dimensions of the playing field?

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  1. 21 February, 19:32
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    P = 2 (L + W)

    P = 490

    L = 4W - 5

    now we sub and solve

    490 = 2 (4W - 5 + W)

    490 = 2 (5W - 5)

    490 = 10W - 10

    490 + 10 = 10W

    500 = 10W

    500/10 = W

    50 = W <===

    L = 4W - 5

    L = 4 (50) - 5

    L = 200 - 5

    L = 195 <===
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