Jim has calculated the area of a rectangle to be x^3 + x^2 + x + 1. If the width of the rectangle is x + 1, then its length is

A) x^2 + 1

B) x^2 + x + 1

C) x^3 + x^2

D) x^3 + x^2 + x

Question

17 October, 04:57

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Answers (1)

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Jerimiah Kim · Answer 1

A = x^3 + x^2 + x + 1

A = x^2 (x + 1) + (x+1)

A = (X + 1) (x^2 + 1)

W = x + 1

so L = x^2 + 1 because A = L*W

answer

A) x^2 + 1

Jim has calculated the area of a rectangle to be x^3 + x^2 + x + 1. If the width of the rectangle is x + 1, then its length isA) x^2 + 1B) x^2 + x + 1C) x^3 + x^2D) x^3 + x^2 + x