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18 July, 14:17

A group of professors investigated first-year college students' knowledge of astronomy. One concept of interest was the Big Bang theory of the creation of the universe. In a sample of 149149 freshmen students, 3232 believed that the Big Bang theory accurately described the creation of planetary systems. Based on this information, is it correct at the alphaαequals=0.100.10 level of significance to state that more than 20% of all freshmen college students believe the Big Bang theory describes the creation of planetary systems? State the null and alternative hypotheses. Choos

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  1. 18 July, 14:19
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    Step-by-step explanation:

    The question is incomplete. The complete question is:

    A group of professors investigated first-year college students' knowledge of astronomy. One concept of interest was the Big Bang theory of the creation of the universe. In a sample of 149 freshmen students, 32 believed that the Big Bang theory accurately described the creation of planetary systems. Based on this information, is it correct at the alpha = 0.01 level of significance to state that more than 20% of all freshmen college students believe the Big Bang theory describes the creation of planetary systems? State the null and alternative hypotheses. Choose the correct answer below. H_0: p = 0.20 H_a: p not equal to 0.20 H_0: p not equal to 0.20 H_a: p = 0.20 H_0: p = 0.20 H_a: p 0.20 If alpha = 0.05, find the rejection region for the test. Choose the correct answer below. z > 1.645 z > 1.96 z

    Solution:

    We would set up the null and alternative hypothesis. The correct options are

    For null hypothesis,

    p ≥ 0.2

    For alternative hypothesis,

    p < 0.2

    This is a left tailed test.

    Considering the population proportion, probability of success, p = 0.2

    q = probability of failure = 1 - p

    q = 1 - 0.2 = 0.8

    Considering the sample,

    Sample proportion, P = x/n

    Where

    x = number of success = 32

    n = number of samples = 149

    P = 32/149 = 0.21

    We would determine the test statistic which is the z score

    z = (P - p) / √pq/n

    z = (0.21 - 0.2) / √ (0.2 * 0.8) / 149 = 0.31

    The calculated test statistic is 0.31 for the right tail and - 0.31 for the left tail

    Since α = 0.05, the critical value is determined from the normal distribution table.

    For the left, α/2 = 0.05/2 = 0.025

    The z score for an area to the left of 0.025 is - 1.96

    For the right, α/2 = 1 - 0.025 = 0.975

    The z score for an area to the right of 0.975 is 1.96

    In order to reject the null hypothesis, the test statistic must be smaller than - 1.96 or greater than 1.96

    Therefore, the rejection region is z > 1.96
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