X+3, - 2x^ (2) - 6x, 4x^ (3) + 12x^ (2) what is the 8th term in this geometric sequence

a8 = - 128x^8 - 384x^7

Step-by-step explanation:

The formula for the general term of a geometric sequence with first term a1 and common ratio r is ...

an = a1·r^ (n-1)

Here, we have a1 = (x+3) and r = (-2x^2-6x) / (x+3) = - 2x. Then the 8th term is ...

a8 = (x+3) (-2x) ^ (8-1)

a8 = - 128x^8 - 384x^7