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22 November, 19:13

What is the derivative of 5cos^2 (pi) (t) ? ... ?

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  1. 22 November, 19:38
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    The answer is

    we know that (cosu (t)) ' = - u ' (t) sin u (t)

    so (cos^2 (pi) (t)) ' = 2 (-pi sin pit) cospit

    and finally the answer is

    [5cos^2 (pi) (t) ] ' = - 10 pi sin pit cospit
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