What's the vertex of f (x) = (x-4) ^2+7

(4,7)

Step-by-step explanation:

The equation for a parabola can be written as

y = a (x-h) ^2 + k where (h, k) is the vertex

given f (x) = (x-4) ^2+7

The vertex is (4,7)

vertex is 4

Step-by-step explanation:

y = (x-4) ^2 + 7

(x-4) (x-4)

x * x = x^2

x * - 4 = - 4x

-4 * x = - 4x

-4 * - 4 = 16

x^2 - 8x + 16

y = x^2 - 8x + 16 + 7

y = x^2 - 8x + 23

a b c

formula to find vertex: - b / 2a

= - b / 2a

= - (-8) / 2 (1)

= 8 / 2

= 4

vertex = 4

(what i did was work out the exponent outsite the parentesis then i got the equation i wanted, and from that equation i used the formula to find the vertex and i just plugged the numbers of the equation into the formula and work it out)