Triangle PQR has coordinates P (-8,3), Q (-8,6), R (-3,6). If the triangle is translated by using the rule (x, y) (x+4, y-6) what are the coordinates of triangle P'Q'R'?

P' = (-4,-3)

Q' = (-4,0)

R' = (1,0)

Step-by-step explanation:

The transformation increases the value of the xth-coordinate of each vertex by 4 and decreases the value of the yth-coordinate by 6. We just need to compute this operations in each vertex P Q and R of the triangle. Therefore we have that

P' = (-8+4,3-6) = (-4,-3)

Q' = (-8+4,6-6) = (-4,0)

R' = (-3+4,6-6) = (1,0)