Ask Question
17 March, 23:45

An isotope decays at a rate of - 0.0049% per year. Find the half life. (show the work)

+4
Answers (1)
  1. 17 March, 23:57
    0
    14,146 years

    Step-by-step explanation:

    The annual multiplier is (1 - 0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.

    0.5 = 0.999951^t

    log (0.5) = t·log (0.999951)

    log (0.5) / log (0.999951) = t ≈ 14,145.514

    The half-life is about 14,146 years.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An isotope decays at a rate of - 0.0049% per year. Find the half life. (show the work) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers