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23 January, 12:52

If a vector's magnitude is 36 units right and 33 units up, what's the approximate magnitude of a vector that's one-third the length of the first vector? A. 48.8 B. 16.3 C. 12.2 D. 24.4

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  1. 23 January, 13:14
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    The correct option is B. 16.3

    Step-by-step explanation:

    We are given a vector with components

    V = 36x + 33y

    To solve this problem, we find its magnitude

    |V| = SQRT (36^2 + 33^2)

    |V| = SQRT (2385)

    |V| = 48.836

    To find the magnitude of the new vector we divide by three the previous quantity

    |V2| = 48.836/3 = 16.278
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