The perimeter of a rectangle is twice the sum of its length and its width. The perimete is 28 meters and its length is 2 meters more than twice its width. What is its length?

Let l be length and w be width.

So the problem already gave you what a perimeter is, which is 2l + 2w.

Now it says perimeter is 28, so 2l + 2w = 28.

Then it says length is 2 more than twice its width, so l = 2w + 2.

Now substitute.

2 (2w + 2) + 2w = 28

4w + 4 + 2w = 28

6w = 24

w = 4

Now substitute w back in l = 2w + 2

l = 2 (4) + 2

l = 10