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8 September, 09:18

Website A offers tickets to an event for $4.50 each plus a $12.25 handling fee, while Website B offers the tickets for $6.00 plus a $1.75 handling fee. Find how many tickets need to be purchased in order for the cost to be the same?

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  1. 8 September, 09:23
    0
    The cost through each website is a linear equation (y = mx+b).

    Slope (m) is a rate and the fees are the y-intercept (b).

    website A.

    y = 4.5x + 12.25

    website B.

    y = 6x + 1.75

    set the cost (y) equal and solve for the number of tickets (x).

    6x + 1.75 = 4.5x + 12.25

    6x - 4.5x = 12.25 - 1.75

    1.5x = 10.5

    x = 10.5/1.5

    x = 7
  2. 8 September, 09:33
    0
    9.75 because when you add 4.50 and 12.50 you'll get 16.75. Then you add 6.00 and 1.75 and get 7.75. Then you take 16 and minus it by 7 and you'll get 9 and now you add

    .75 to the 9 and you'll get 9.75
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