Ask Question
7 June, 20:34

I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)

ii) How many solutions has the equation sin2x + 3cos2x = 0 for 0 < = X <=1080°?

+4
Answers (1)
  1. 7 June, 20:51
    0
    Get rid of cos2x by dividing both the values. So Sin2x/cos2x + 3cos2x/cos2x.

    Tan2x = 3

    2x = - 71.5 so x is - 35.6

    Use the quadrant method and add 360 to the two values you get.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°) ii) How many solutions has the equation sin2x + 3cos2x = 0 for 0 < = X ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers