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Mathematics
16 February, 15:51
How do you solve (-2pq³) (5p²q²) (-3q⁴) ?
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Blaine Chambers
16 February, 15:55
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Multiply the coefficents first (-2*5*-3) = 30
then by the exponent rules multiply the powers of the "p's" (1*2) = 2
then same thing with the "q's" (3*2*4) = 24
then put everything together = 30p^2q^24
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