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24 November, 20:00

What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at (7,0) ?

f (x) = (x - 2) (x - 7)

f (x) = (x + 2) (x + 7)

f (x) = (x - 3) (x + 7)

f (x) = (x + 3) (x - 7)

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Answers (2)
  1. 24 November, 20:01
    0
    f (x) = (x + 3) (x - 7)

    Step-by-step explanation:

    its d i had the test
  2. 24 November, 20:24
    0
    "f (x) = (x + 3) (x - 7) "

    Step-by-step explanation:

    If the vertex is (h, k), then the quadratic is can be written in the form:

    y = a (x-h) ^2 + k

    So it will be:

    y = a (x-2) ^2 - 25

    Now, to find a, we need the x-intercept (which is 7), so we plug in 7 into x and 0 into y and solve for a:

    0 = a (7-2) ^2 - 25

    0 = a (5) ^2 - 25

    0 = 25a - 25

    a = 1

    THus, we can write:

    y = (x-2) ^2 - 25

    Expanding this, we get:

    y = x^2 - 4x + 4 - 25

    y = x^2 - 4x - 21

    y = (x-7) (x+3)

    THis is correct answer.
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