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30 April, 05:10

Consider the equation 3tan^2 (x) - 1=0.

the solutions of this equation over the interval {0, pi} are?

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  1. 30 April, 05:22
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    3tan^2 (x) - 1=0

    => 3tan^2 (x) = 1

    => tan^2 (x) = 1/3

    => tan (x) = √ (1/3) and - √ (1/3)

    => x = tan^-1 * (√ (1/3)) and tan^-1 * (-√ (1/3))
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