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17 September, 04:03

If a=4, b=5, and 2 (ab + bc + ca) = 202, find the value of c

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Answers (2)
  1. 17 September, 04:12
    0
    c = 9

    Step-by-step explanation:

    First we need to substitute in our known values:

    2 ((4X5) + 5c + 4c) = 202

    Next we can do the inner multiplication and combine our like terms:

    2 (20 + 9c) = 202

    Now we distribute the 2:

    40 + 18c = 202

    Subtract 40 from both sides:

    18c = 162

    Lastly, divide both sides by 18 to get:

    c = 9

    Check our work:

    2 ((4X5) + (5X9) + (9X4)) = 202

    2 (20 + 45 + 36) = 202

    2 (101) = 202

    202 = 202
  2. 17 September, 04:23
    0
    in this equation c = 9
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