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17 October, 02:15

Molly earned a score of 940 on a national achievement test. the mean test score was 850 with a standard deviation of 100. what proportion of students had a higher score than molly? (assume that test scores are normally distributed.)

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  1. 17 October, 02:28
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    Solution: We are given:

    μ=850,σ=100

    We have to find P (x>940)

    We need to find the z score:

    z = (x-μ) / σ

    = (940-850) / 100

    =0.9

    Now we need to find P (z>0.9)

    Using the standard normal table, we have:

    P (z>0.9) = 0.1841

    Therefore 0.1841 or (18.41%) of students had a higher score than molly
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