What is the solution to 4+5e^x=2=11?

Ax = In7/5-2

Bx = In7/5+2

Cx = In35-2

D x=In35+2

4+5e^ (x-2) = 11

4+5e^ (x-2) - 4=11-4

5e^ (x-2) = 7

5e^ (x-2) / 5 = 7/5

e^ (x-2) = 7/5

ln e^ (x-2) = ln (7/5)

(x-2) ln e = ln (7/5)

(x-2) (1) = ln (7/5)

x-2=ln (7/5)

x-2+2=ln (7/5) + 2

x = ln (7/5) + 2

Answer: Otion B. x = ln (7/5) + 2