A movie club charges a one time membership fee (price to be part of the club) of 30$ which allows (let's) members to buy movie tickets for 8$ each another club does not charge a membership fee and sells tickets for 11$ each how many movie tickets must a member (a person in a club) purchase for the cost of the two clubs to be equal

Question

James Roach

Mathematics

20 November, 23:31

A movie club charges a one time membership fee (price to be part of the club) of 30$ which allows (let's) members to buy movie tickets for 8$ each another club does not charge a membership fee and sells tickets for 11$ each how many movie tickets must a member (a person in a club) purchase for the cost of the two clubs to be equal

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Answers (1)

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Malaki Curry · Answer 1

10 tickets

Step-by-step explanation:

The difference in club fee is $30. The difference in ticket price is $3. It takes 30/3 = 10 tickets to make up the difference in club fee.

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The cost of 10 tickets for "a movie club" is $30 + 10*8 = $110.

The cost of 10 tickets for "another club" is $11*10 = $110.

The two clubs have equal costs for purchase of 10 tickets.