100
10, UUS
11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20
meters above the ground. The height h (in meters) of the ball at time t in seconds) after it
is thrown can be found by h (t) = - 5t^2 + 15t + 20. Find the time when the ball is again 20
meters above the ground.
A
1 second
(B
2 seconds
C
3 seconds
D
4 seconds
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “100 10, UUS 11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20 meters above the ground. The height ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
Can somebody solve this y = - 3/4+25
Answers (2)
Solve for 52=4 (8m-5) - 8 (m-6)
Answers (1)
Two angles are vertical angles. If the angles are also complementary angles, what is the degree of the angle
Answers (1)
One of the earliest electric drone models was able to travel at a top speed of 3 miles per hour, or 4.8 kilometers per hour. Today drone's can travel at a top speed of 14 miles per hour. How many kilometers per hour is that ?
Answers (1)
7*7 8*8 9*9 10*10 11*11
Answers (1)
New Questions in Mathematics
What is the radius of a circle whose equation is x2 y2 - 10x 6y 18 = 0?
Answers (1)
Y=x+4 and y-4=x. Is there no solution one solution or infinitely many
Answers (1)
How do you recognize a central angle of a circle
Answers (1)
Formulate three linear inequalities that are equivalent to y < - 3.
Answers (1)
25 more than 50 as an expression
Answers (1)