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20 July, 12:17

Suppose a bag contains 4 white chips and 6 black chips what is the probability of randomly choosing a white chip not replacing it and then randomly choosing another white chip

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  1. 20 July, 12:21
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    Number of white chips = 4

    Number of black chips = 6

    Total number of chips = 4 + 6 = 10

    Choosing the first white chip:

    p (white chip) = 4/10 = 2/5

    Now the numbers are:

    Number of white chips = 3

    Number of black chips = 6

    Total number of chips = 3 + 6 =

    Choosing the second white chip:

    p (white chip) = 3/9 = 1/3

    p (white chip followed by white chip) = 2/5 * 1/3 = 2/15
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