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14 June, 13:13

What are the real zeros of x3 + 4x2 - 9x - 36?

A. 1, 2, 3

B. - 6, 2, 3

C. - 4, - 3, 3

D. - 1, 2, 18

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  1. 14 June, 13:27
    0
    C

    Step-by-step explanation:

    x^3+4x^2-9x-36=0

    or x² (x+4) - 9 (x+4) = 0

    or (x+4) (x²-9) = 0

    or (x+4) (x+3) (x-3) = 0

    x=-4,-3 or 3
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