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3 November, 22:53

Given the size and mass of each of the solid cubes X and Y, how many

times is the density of cube X greater than the density of cube Y?

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Answers (1)
  1. 3 November, 23:15
    0
    Since

    density = mass/volume (which is just another word for size)

    density of cube X = (cube X's mass) / (cube X's volume)

    lets name " (cube X's mass) / (cube X's volume) " as "x"

    density of cube Y = (cube Y's mass) / (cube Y's volume)

    lets name " (cube Y's mass) / (cube Y's volume) " as "y"

    then to calculate how many times is the density of cube X to density of cube Y, then it will be x/y

    if calculating how many times greater, then it is (x-y) / y

    though the phrase "how many times greater" can also mean "how many times".
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