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Which quadratic equation defines the function that has zeros at - 8 and 6?

A. x^2 + 2x - 48 = 0

B. x^2 - 2x - 48 = 0

C. x^2 + 2x + 48 = 0

D. x^2 - 2x + 48 = 0

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Answers (1)
  1. 10 April, 02:06
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    Answer: it is A

    Step-by-step explanation:

    x^2+2x-48=0

    x^2+8x-6x-48=0

    x * (x+8) - 6 (x+8) = 0

    (x+8) * (x-6) = 0

    x+8=0

    x-6=0

    x=-8

    x=6
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