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1 January, 15:48

Y=a (x+6) (x+1) (x+1) (x-3) (x-5)

How do I factor that into standard form : (?

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  1. 1 January, 15:54
    0
    First, expand out the brackets:

    y = ax + 6a + ax + a + ax + a + ax - 3a + ax - 5a

    Then simplify:

    y = ax^2
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