A bag contains 222 red marbles, 222 green marbles, and 444 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

1/14

Step-by-step explanation:

Assuming you mean that there are 2 red, 2 green, and 4 blue marbles, there are a total of 8 marbles.

On the first draw, the probability the marble is red is 2/8.

On the second draw, there's one less marble, so the probability of selecting a green marble is 2/7.

The total probability is:

2/8 * 2/7 = 1/14