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28 November, 17:33

Solve the following pair of simultaneous equations.

2x + 3y = 6

3x - 2y = 22

+3
Answers (2)
  1. 28 November, 17:43
    0
    (6, - 2)

    Step-by-step explanation:

    Given the 2 equations

    2x + 3y = 6 → (1)

    3x - 2y = 22 → (2)

    Eliminate the y - term by multiplying (1) by 2 and (2) by 3

    4x + 6y = 12 → (3)

    9x - 6y = 66 → (4)

    Add (3) and (4) term by term

    13x = 78 (divide both sides by 13)

    x = 6

    Substitute x = 6 into either of the 2 equations and solve for y

    Using (1), then

    (2 * 6) + 3y = 6

    12 + 3y = 6 (subtract 12 from both sides)

    3y = - 6 (divide both sides by 3)

    y = - 2

    Solution is (6, - 2)
  2. 28 November, 17:50
    0
    The answer for the first one is y=-2/3x+2 and the second one is y=3/2x-11
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