A basketball is thrown with an initial upward velocity of 23 feet per second from a height of 7 feet above the ground. The equation h=-16t2+23t+7h=-16t2+23t+7 models the height in feet t seconds after the basketball is thrown. After the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground. About how long after it was thrown does it go into the hoop? Select one: a. 1.29 seconds b. 1.44 seconds c. 1.70 seconds

Question

Zachary Bean

Mathematics

28 November, 20:47

A basketball is thrown with an initial upward velocity of 23 feet per second from a height of 7 feet above the ground. The equation h=-16t2+23t+7h=-16t2+23t+7 models the height in feet t seconds after the basketball is thrown. After the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground. About how long after it was thrown does it go into the hoop? Select one: a. 1.29 seconds b. 1.44 seconds c. 1.70 seconds

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Jonathan Houston · Answer 1

10=-16t^2+23t+7 subtracting the right side from both sides

16t^2-23t+3=0 using the quadratic formula

t = (23±√337) / 32, since we are looking for the larger value of t, as the ball in returning downward ...

t = (23+√337) / 32

t≈1.29 seconds