I genuinely have no idea what this is asking from me

Find the solution set of each equation if the replacement sets are y: {1,3,5,7,9}

and z:{10, 12, 14, 16, 18).

11. z + 10 = 22

12. 52 = 4z

13. (15/y) = 3

14. 17 = 24-y

15. 2z - 5 = 27

16. 4 (y + 1) = 40

17. 22 = (60/y) + 2

18. 111 = z^2 + 11

Step-by-step explanation:

Basically, it wants you to solve each equation for the variable. If the answer (s) is one of the numbers in the replacement set, then that's a number in the solution set. Otherwise, there's no solution.

For example:

11. z + 10 = 22

z = 12

12 is one of the numbers in the replacement set for z, so the solution set is {12}.

12. 52 = 4z

z = 13

13 is not one of the numbers in the replacement set for z. There is no solution.