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6 September, 01:38

Suppose a smokejumper jumps from an altitude of 13,000 feet. If he's 65 percent of his way down, how far is he from the ground?

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Answers (2)
  1. 6 September, 01:41
    0
    Answer: 4550 feet to the ground

    Step-by-step explanation: 13000 ft x 65% =

    8450 feet

    13000 ft

    - 8450 ft

    = 4550 ft to the ground
  2. 6 September, 01:54
    0
    4550 feet

    Step-by-step explanation:

    13000 x. 65% = 8450 feet he has descended

    13000 - 8450 = 4550 feet from the ground
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