The table below shows the distance d (t) in feet that an object travels in t seconds.

t d (t)

(second) (feet)

1 15

2 60

3 135

4 240

What is the average rate of change of d (t) between 2 seconds and 4 seconds and what does it represent?

A) 50 m/s; it represents the average speed of the object between 2 seconds and 4 seconds

B) 90 m/s; it represents the average speed of the object between 2 seconds and 4 seconds

C) 90 m/s; it represents the average distance traveled by the object between 2 seconds and 4 seconds

D) 50 m/s; it represents the average distance traveled by the object between 2 seconds

Question

Guest

Mathematics

18 February, 23:49

The table below shows the distance d (t) in feet that an object travels in t seconds.

t d (t)

(second) (feet)

1 15

2 60

3 135

4 240

What is the average rate of change of d (t) between 2 seconds and 4 seconds and what does it represent?

A) 50 m/s; it represents the average speed of the object between 2 seconds and 4 seconds

B) 90 m/s; it represents the average speed of the object between 2 seconds and 4 seconds

C) 90 m/s; it represents the average distance traveled by the object between 2 seconds and 4 seconds

D) 50 m/s; it represents the average distance traveled by the object between 2 seconds

+5

Answers (1)

Know the Answer?

Watson · Answer 1

B) 90 m/s; it represents the average speed of the object between 2 seconds and 4 seconds

proof

the main formula is v = D / Dt, D=Dfinal - Dinitial

Dt = tfinal - tinitial

so between t=2 and t = 4, V = 240-60 / 4-2 = 90m/s