If y varies directly as x^2 and y = 72 when x = 3, what is the value of y when x = 6?

Answer:288

Step-by-step explanation:

If y varies directly as x^2

i. e y varies directly as x * x

and y = 72, when x = 3

therefore, 72 = k * 3*3 9 (where k is constant)

72=k9

k = 72/9

=8

The value of y, when x = 6 will be

y = 8 * 6^2

8*36 = 288