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17 November, 21:48

If y varies directly as x^2 and y = 72 when x = 3, what is the value of y when x = 6?

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  1. 17 November, 22:17
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    Answer:288

    Step-by-step explanation:

    If y varies directly as x^2

    i. e y varies directly as x * x

    and y = 72, when x = 3

    therefore, 72 = k * 3*3 9 (where k is constant)

    72=k9

    k = 72/9

    =8

    The value of y, when x = 6 will be

    y = 8 * 6^2

    8*36 = 288
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