The measures of the interior angles of a pentagon are 2x, 6x, 4x-6,2x-16 and 6x+2. What is the measure, in degrees, of the largest angle?

170°

Step-by-step explanation:

The formulae for getting the interior sides of an angle is 180 (n-2) where n is there number of sides. And pentagon has 5 sides.

180 (5-2)

180 (3) = 540°

Additions of the must just give 540°

2x+6x + (4x-6) + (2x-16) + (6x+2) = 540°

Collect like terms

2x+6x+4x+2x+6x-6-16+2=540°

20x-20=540

20x=540+20

20x=560

x=560/20

x=28°

Which of these sides gives the greatest.

2x=2 (28) = 56°

6x=6 (28) = 168°

4x-6=4 (28) - 6=112-6=108°

2x-16=2 (28) - 16=56-15=40°

6x+2=6 (28) + 2=168+2=170°

The greatest of them is (6x+2) °=170°