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29 January, 09:29

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v (t) = 6t2 - 18t + 12 (in feet/sec).

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  1. 29 January, 09:33
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    It moves 0 feet.

    Substituting 2 for t, we have:

    v (t) = 6 (2²) - 18t+12 = 6*4-36+12 = 24-36+12=0
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