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17 August, 19:23

8z=4 (2z+1) show step by step

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  1. 17 August, 19:39
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    8z=4 (2z+1)

    First you would distribute the constant into the numbers in the parentheses. so

    8z=8z+4

    then you would combine like terms which in this case would result in a zero.

    8z-8z=0 So the z would be zero or no solution.
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