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28 January, 13:33

What are the solutions to the following system of equations? y = x^2 - 3x + 3

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  1. 28 January, 13:55
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    x = 3/2 + root (3) / 2 or x = 3/2 - root (3) / 2

    In vertex form the equation is y = (x - 3/2) ^2 + 3/4

    Step-by-step explanation:

    y = x^2 - 3x + 3

    y = x^2 - 3x + 9/4 - 9/4 + 3

    y = (x - 3/2) ^2 + 3/4

    I think you want to find the roots to the equation, right?

    so

    y = (x - 3/2) ^2 + 3/4 = 0

    (x - 3/2) ^2 = - 3/4

    x - 3/2 = root (-3/4)

    x = 3/2 + root (3) / 2 or x = 3/2 - root (3) / 2
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