What's the answer for the sum of three consecutive numbers is 126. What is the smallest of the three numbers

To solve this problem, start with the smallest and call it n. The next three numbers are n+1 and n+2, so the sum of these numbers is:

n + (n+1) + (n+2) = 126.

This equation reduces to:

3n+3 = 126 subtracting 3 from either side makes it

3n = 123 and dividing either side by 3 means

n = 41

The smallest is 41 so the largest is 43

126 divided into 3 equal parts is 42 in each part.

Lay the parts out in a row on the table.

Take 1 away from one part, and drop it onto a different part.

Now you have your 3 consecutive numbers, made from the 3 equal parts of 126.

They are 41, 42, and 43.