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Sally can paint a room in 7 hours while it taks steve 9hours to finsh the same room. how ling will it take them to paint if they worked together?

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  1. 3 June, 18:13
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    Sally alone can paint the room in 7 hours.

    In 7 hours Sally alone does the job.

    In 1 hour Sally would do (1/7) of the job.

    Steve can paint it alone in 9 hours.

    In 9 hours Steve alone does the job.

    In 1 hour Steve would do (1/9) of the job.

    Both working together in 1 hour would do: (1/7) + (1/9).

    (1/7) * (9/9) + (1/9) * (7/7) = 9/63 + 7/63 = (9 + 7) / 63 = 16/63

    In 1 hour both will have done (16/63) of the job.

    16/63 of the job will be done in 1 hour by both.

    Therefore a 1 whole fraction of the job will be done in: 1 hour : 16/63

    = 1 hour * 63/16

    = 63/16 hours = 3.9375 hours

    It would take both 63/16 hours or 3.9375 hours.
  2. 3 June, 18:23
    0
    How much part can sally paint in an hour?

    a : 7 = a/7

    And what about Steve?

    a : 9 = a/9

    Where, a is the total area of the room.

    So, let the time taken by both of them to paint the room together be 't'

    So,

    t (a/7 + a/9) = a

    t (9a/63 + 7a/63) = a

    t (16a/63) = a

    t = 63/16 ≈ 4 hr
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