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Lillian Foster
Mathematics
18 January, 17:27
Are 5y=15-2x and 2/5x - 4 = y perpendicular
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Selina Sherman
18 January, 17:32
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When 2 lines are perpendicular, they have opposite-reciprocal slopes. This means that they're of the opposite signs and reciprocals of each other.
So start off by putting each equation into slope-intercept form:
5y = 15-2x
y = 3 - 2/5x
y = - 2/5x + 3
2/5x-4 = y
y = 2/5x-4
Take the slopes of both lines and compare:
Line 1 > - 2/5
Line 2 > 2/5
The lines do have opposite signs but they're not reciprocals. (If they were, the slopes should've been - 2/5 and 5/2). Therefore, NO they're not perpendicular.
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Joseph Holden
18 January, 17:34
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No, in order for two pairs of lines to be perpendicular, their slopes need to be opposite and reciprocal. If we divide by 5 to isolate the y on the first one then the slope is - 2/5. The slope on the other is 2/5. Yes they are opposites but not reciprocals. So the answer is no.
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