Find other values of a, b, and c so that log (a) + log (b) + log (c) = log (a + b + c).

Step-by-step explanation:

Given:

log (a) + log (b) + log (c) = log (a + b + c)

We know that by property

log (a) + log (b) + log (c) = log (abc)

Therefore,

log (abc) = log (a + b + c)

Thus,

(abc) = (a + b + c)

Thus when a = b = c = 0,

then (abc) = (a + b + c)

0 = 0

and when a = 1, b = 2, c = 3,

then (abc) = (a + b + c)

(1 x 2 x 3) = (1 + 2 + 3)

6 = 6