Steven needs to select a 5-digit code to turn off his alarm system. How many different codes can be formed if no digits can be repeated?

Question

Valery Hendricks

Mathematics

20 April, 07:09

Steven needs to select a 5-digit code to turn off his alarm system. How many different codes can be formed if no digits can be repeated?

+5

Answers (2)

Know the Answer?

Avery Blanchard · Answer 1

Answer: Just one

Step-by-step explanation:

if you can't repeat any digits the first code will go 12345 and just like you run out of digits

Carsen Stein · Answer 2

100,000

Step-by-step explanation:

There are 5 digits in the number. To form a five digit number, we can have any digit in the 5th place except 0 because 0 will cause the number to be a 4 digit one.

So, the number of ways we can fill the 5th place is 9.

For the 4th place, we can have any digit from 0-9. Same goes for the 3rd, 2nd as well as the One's place.

Finally we can multiply them and get your answer which is 9*10*10*10*10 which results in 90000.

Unless of course this is an actual code in which the 5th place can be 0. Then that would make the amount 10*10*10*10*10, or 100,000