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Valery Hendricks
Mathematics
31 January, 10:52
Steven needs to select a 5-digit code to turn off his alarm system. How many different codes can be formed if no digits can be repeated?
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Avery Blanchard
31 January, 11:21
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Answer: Just one
Step-by-step explanation:
if you can't repeat any digits the first code will go 12345 and just like you run out of digits
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Carsen Stein
31 January, 12:45
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100,000
Step-by-step explanation:
There are 5 digits in the number. To form a five digit number, we can have any digit in the 5th place except 0 because 0 will cause the number to be a 4 digit one.
So, the number of ways we can fill the 5th place is 9.
For the 4th place, we can have any digit from 0-9. Same goes for the 3rd, 2nd as well as the One's place.
Finally we can multiply them and get your answer which is 9*10*10*10*10 which results in 90000.
Unless of course this is an actual code in which the 5th place can be 0. Then that would make the amount 10*10*10*10*10, or 100,000
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