A discount book store sells hardcover books for $8 each and paperbacks for $4 each. The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold.

8 h + 4 p = 160. p = 4 h + 2.

What is Jean-Paul's error?

Question

Yurem Douglas

Mathematics

10 December, 19:46

A discount book store sells hardcover books for $8 each and paperbacks for $4 each. The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold.

8 h + 4 p = 160. p = 4 h + 2.

What is Jean-Paul's error?

+5

Answers (1)

Know the Answer?

Joshua Reeves · Answer 1

Step-by-step explanation:

paperbacks (p) for $4 and hardbacks (h) for $ 8 ... totaling 160

8h + 4p = 160 ... he got this one right

hardcover (h) = 2 more then 4 times the number of paperbacks (p)

h = 4p + 2

his mistake:

he put p = 4h + 2 ... meaning paperbacks = 2 more then 4 times the hardcover (h)