The general term of a geometric sequence is tn = 6 (1 6) n - 1, where n ∈ N and n ≥ 1. Which of these is the sequence? A) 1 6, 1 36, 1 216, 1 1296, 1 7776, 1 46656, ... Eliminate B) 1, 1 6, 1 36, 1 216, 1 1296, 1 7776, ... C) 6, 1 6, 1 36, 1 216, 1 1296, 1 7776, ... D) 6, 1, 1 6, 1 36, 1 216, 1 1296, ...

Question

Jorge

Mathematics

20 October, 07:10

The general term of a geometric sequence is tn = 6 (1 6) n - 1, where n ∈ N and n ≥ 1. Which of these is the sequence? A) 1 6, 1 36, 1 216, 1 1296, 1 7776, 1 46656, ... Eliminate B) 1, 1 6, 1 36, 1 216, 1 1296, 1 7776, ... C) 6, 1 6, 1 36, 1 216, 1 1296, 1 7776, ... D) 6, 1, 1 6, 1 36, 1 216, 1 1296, ...

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Answers (1)

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Martha Walls · Answer 1

Tn = 6 (1/6) ^n-1

the 6 is the first number ... the common ratio is 1/6 ... that means to find the next number in the sequence, u multiply by 1/6

starts with 6 ...

6 * 1/6 = 1

1 * 1/6 = 1/6

1/6 * 1/6 = 1/36

1/36 * 1/6 = 1/216

1/216 * 1/6 = 1/1296

1/1296 * 1/6 = 1/7776

so ur sequence is : 6,1,1/6,1/36,1/216,1/1296,1/7776 ...