John bikes 22km per hour and starts at mile 10. Gwynn bikes 28 km per hour and starts at mile 0. Which system of linear equations represents this situation?

If j is the distance in km John reaches after time t hours, and g is the same for Gwynn, the equations are

j=10+22t and g=28t.

If x is the distance at which they meet the equations form a system from which t, when they meet, can be calculated: 10+22t=28t, 6t=10, t=5/3=1 hour 40 minutes. And they meet at 28*5/3=10+22*5/3=46.67km.