Michelle had a birthday party. She bought a bag of candy with 96 Starbursts, 72 Hershey's, and 68 Reese's. She wants to use all the candy she bought to make goody bags with the same amount of Starbursts, Hershey's and Reese's in each bag. What is the largest number of bags she can make?

Question

Eileen Hancock

Mathematics

25 June, 05:13

Michelle had a birthday party. She bought a bag of candy with 96 Starbursts, 72 Hershey's, and 68 Reese's. She wants to use all the candy she bought to make goody bags with the same amount of Starbursts, Hershey's and Reese's in each bag. What is the largest number of bags she can make?

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Answers (1)

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Nadia · Answer 1

4 goody bags.

Step-by-step explanation:

We have been given that Michelle bought a bag of candy with 96 Starbursts, 72 Hershey's, and 68 Reese's.

To find the largest number of goody bags with the same amount of Starbursts, Hershey's and Reese's in each bag, we need to find the greatest common factor of 96, 72 and 68.

Factors of 96 are: 1, 2, 3, 4, 24, 32, 48, 96.

Factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.

Factors of 68 are: 1, 2, 4, 17, 34, 68.

We can see that greatest common factor of 96, 72 and 68 is 4, therefore, the largest number of bags that Michelle can make with 96 Starbursts, 72 Hershey's, and 68 Reese's is 4 bags.