Shelby graphs the function f (x) = (x-3) 2 - 1. Which statements are true about the graph? Check all that apply

While your statements are missing, there are a few things we can tell about the graph from the equation:

The vertex is at (3, - 1). We know this because the equation is in vertex form,

y=a (x-h) ²+k, where (h, k) is the vertex.

The graph opens upward and has a minimum. This is because there is no negative before the squared term.

The y-intercept of the graph is at (0, 8). We know this because if we substitute 0 for x, we have

y = (0-3) ²-1 = (-3) ²-1 = 9-1 = 8